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Mathematics 15 Online
OpenStudy (anonymous):

if A = {1,2,3,4} and R is a relation on itself such that R = {(1,1), (2,2), (3,3) } is R reflexive?

myininaya (myininaya):

Do you have for every x in A we also have (x,x) is in R?

OpenStudy (anonymous):

(4,4) isn't

OpenStudy (anonymous):

in R

myininaya (myininaya):

this question means do you have (1,1), (2,2),(3,3),and (4,4)? and you are right so it isn't reflexive

myininaya (myininaya):

you have to have for all!!!!! x in A we have (x,x) is in R That for all part being the key word.

OpenStudy (anonymous):

oh I thought I only need to check those x in A that are in R

myininaya (myininaya):

i think you are thinking of symmetry and transitive because we don't have to have for all a,b in A that (a,b) and (b,a) is in R the definition for symmetry is if you have (a,b) in R then you must have (b,a)

OpenStudy (anonymous):

I see. thank you!

myininaya (myininaya):

so if we define a relation R on A that relation R being {(1,3),(3,1)} R wouldn't be reflexive R would be symmetric since we do have (1,3) but we also have (3,1) R is also transitive Remember if then statements are only false when you have true if and a false then. But we couldn't find a case where the if part was true so we don't have to worry if our then part is true or false because our if then statement is true I think they use the phrase "it is vacuously true"

OpenStudy (anonymous):

lol i was gonna point that out

OpenStudy (anonymous):

so if R = {(1,1)} R is not reflexive R is symmetric R is transitive correct?

myininaya (myininaya):

totally

OpenStudy (anonymous):

got it. Thanks ;)

myininaya (myininaya):

just be careful with those if then statements and you will have to recall your truth tables

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