Question

Solve equation for x, where 0 12 years ago

Answer 1

\[\cos(2x-\frac{ \pi }{ 2 })= -1\]
\[\cos(2x-\frac{ \pi }{ 2 }) = \pi + 2\pi k\]

Answer 2

how do i get cosx by it self?

Answer 3

That's not the best way going about this problem. We should find an angle of cosine that gives us a value of -1. Do you know which angle that is?

Answer 4

cos(pi) = -1

Answer 5

Good! So, we can set pi equal to that argument for the angle! :D
cos(pi) = -1
cos(2x - pi/2) = -1

pi = 2x - pi/2
Solve for x! :D

Answer 6

whoa thats crazy
thanksssss

Answer 7

No prob.