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Can someone help understand how to do this equation: Simplify the expression.
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okay,well first, the exponent 2 is distributed down to every term.
Oh Ok. Gotcha
so it'll be \[(3^2xy^{-1})\div(x ^{-1}y)\]
the negative exponents just mean that it should be a fraction with 1 over it. so \[y^{-1} = \frac{ 1 }{ y }\]
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ok got it.
in essence, if the negative is exponent is on the top, bring it down to make it positive. if it's on the bottom, bring it up to make it positive.
so what's on top after you move the negatives around and what's on the bottom? \[\frac{ 9x*x }{ y*y }\] (sorry if i'm slow, just made an account)
ok and no prob. so would it be 9x2/y2
yup!
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Aight. Awesome thanks for your help
you're welcome :)
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