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Mathematics 8 Online
OpenStudy (anonymous):

Find if the series converges or diverges...

OpenStudy (anonymous):

\[1-\frac{1*3}{3!}+\frac{1*3*5}{5!}-\frac{1*3*5*7}{7!}..+...\]

OpenStudy (anonymous):

I know that it alternates between - and + so its probably (-1)^n(some formula)/(some formula)!

OpenStudy (anonymous):

the bottom pattern is like 1!,3!,5!,7!, so the fomula is probably something like --->even integer -1

OpenStudy (anonymous):

But Im confused about how I can get the top pattern formula

OpenStudy (anonymous):

you know what the top is also probably some--> even integer -1 but how does it keep adding on to the last multiple like that?

OpenStudy (anonymous):

This might help: http://en.wikipedia.org/wiki/Double_factorial

OpenStudy (anonymous):

but what about the top term?

ganeshie8 (ganeshie8):

ive deleted as i saw a mistake in it lol, try to simplify the terms first...

ganeshie8 (ganeshie8):

\(\large \frac{(-1)^{n+1}}{2^{n-1}(n-1)!}\)

ganeshie8 (ganeshie8):

see if this works

OpenStudy (anonymous):

I got it! its (2n-1)! at the bottom and probably the same thing at the top but how does the previous multiplier stay the same?

ganeshie8 (ganeshie8):

i feel top is not that easy to get... could u check if the nth term i gave earlier works ?

ganeshie8 (ganeshie8):

\(\large a_n = \frac{(-1)^{n+1}}{2^{n-1}(n-1)!}\)

ganeshie8 (ganeshie8):

\(\large a_1 = 1 \) \(\large a_2 = -\frac{1}{2} \) \(\large a_3 = \frac{1}{2^2(2!)} \)

ganeshie8 (ganeshie8):

hey let me knw if smthng doesnt make sense..

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