Question

In a certain university course 8 out of every 10 students finish it.
If in this semester 94 students are in the course, how many are expected to finish ?

Answer 1

For 10 students attending, 8 students finish. If we assume the ratio is expected for any amount of attendees:
If 10 students attend, then 8 students succeed.
If 94 students attend, then x students succeed.
Do you know how to write this proportion?

Answer 2

no. it kinda seems like youve taken my question and just re worded it :/ im not that bright so sorry if im a bit slow.

Answer 3

Yep, that's essentially what I did. And its fine.
I reworded it so that the information lines up a bit better.

The ratio is just a division:
\( \dfrac{8 \text{ students finish}}{10\text{ students total}} \) ,

\( \dfrac{ x \text{ students finish}}{94 \text{ students total}} \)
These would be equal. Removing the words, we just have the proportion which we may solve.
\( \dfrac{x}{94} = \dfrac{8}{10} \)

Answer 4

fractions. yay :/ okay so where do i go from here ?

Answer 5

Do you know how to solve a proportion?

Answer 6

I take that as a no?

Answer 7

no i dont :/

Answer 8

I think the phrase "cross-multiply and divide" is often associated with proportions, if that rings a bell.

Answer 9

sort of.

Answer 10

Cross multiply.\[94\times8=?\]Divide\[?\div10=?\]

Answer 11

752

752 divided by 10 = 75.2

Answer 12

That's what I got. :)

Answer 13

so 75 students are expected to finish the course. cant have 75.2 people. and because th is below 5 i round down yeah ?

Answer 14

Yep, that sounds reasonable. Can't really have a fifth of a person finish. :)

Answer 15

That's what I would do.

Answer 16

thanks heaps !!!!! i really appreciate it !

Answer 17

Youŕe welcome!