Identify the oxidation numbers of the following A. Sulfur as a reactant and product in S8+12 O2 --> 8 SO3 B. Nitrogen in the following compounds or ions N2O5 NO3 NO2 Ca3N2
We need to figure out some charges.
Can you tell me what the charge of each S in S8 is?
im am not sure. \[S _{8}\]
\[S _{8}+12O _{2}-->8SO _{3}\]
Ok. Nonmetal bonded to nonmetal is a covalent bond which means electrons are shared, not transferred. So each S has an oxidation number of 0.
Oxygen almost always has an oxidation number of -2 in compounds.
And the oxidation numbers of neutral compounds must sum to 0.
So, since we have 3 oxygens in SO3, the oxidation number from all three oxygens is -6. To sum to 0, the S needs to be +6.
Make sense?
yes. but what about the 12\[O _{2}\]
12O2
Uncombined elements have oxidation number of 0, but the question only asked for the oxidation numbers of S.
oh makes sense
:) Can you try N2O5?
would N be -5
5
Remember that O is virtually always -2.
10
you said because of that oxygen would be -10 and the sum would need to be 0 so Nitrogen needs to be 10
But there are 2 N.
So each one needs to be 5.
I understand why N needs 5 but why does O need 5?
I'm not sure what you mean.
you said each one needs 5 I do understand why nitrogen needs 5 to off set oxygens -10 right?
The oxidation number of N needs to be 5 (total of 10) to balance the oxidation number of O (total of -10).
ok got it. NO3 nitrogen needs 6 right?
Perfect. :)
NO2?
4
Great!
the last one I am stumped
to take a guess 3
Good guess. Remember how I said that oxygen is almost always is -2. Well, group 2 metals are always +2.
The rules are summed up on this website. http://www.chemguide.co.uk/inorganic/redox/oxidnstates.html
-3 then if that is the case
Exactly.
You probably have the rules somewhere in your textbook too.
light bulb. I am starting to understand this chemistry stuff with only 4 weeks left in the semester. awesome.
Nice. Well, better late than never. :)
I have the textbook right next to me and honestly it is like reading a foreign language at times.
Yeah, I know what you mean. Some are better than others.
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