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Chemistry 10 Online
OpenStudy (anonymous):

Identify the oxidation numbers of the following A. Sulfur as a reactant and product in S8+12 O2 --> 8 SO3 B. Nitrogen in the following compounds or ions N2O5 NO3 NO2 Ca3N2

OpenStudy (joannablackwelder):

We need to figure out some charges.

OpenStudy (joannablackwelder):

Can you tell me what the charge of each S in S8 is?

OpenStudy (anonymous):

im am not sure. \[S _{8}\]

OpenStudy (anonymous):

\[S _{8}+12O _{2}-->8SO _{3}\]

OpenStudy (joannablackwelder):

Ok. Nonmetal bonded to nonmetal is a covalent bond which means electrons are shared, not transferred. So each S has an oxidation number of 0.

OpenStudy (joannablackwelder):

Oxygen almost always has an oxidation number of -2 in compounds.

OpenStudy (joannablackwelder):

And the oxidation numbers of neutral compounds must sum to 0.

OpenStudy (joannablackwelder):

So, since we have 3 oxygens in SO3, the oxidation number from all three oxygens is -6. To sum to 0, the S needs to be +6.

OpenStudy (joannablackwelder):

Make sense?

OpenStudy (anonymous):

yes. but what about the 12\[O _{2}\]

OpenStudy (anonymous):

12O2

OpenStudy (joannablackwelder):

Uncombined elements have oxidation number of 0, but the question only asked for the oxidation numbers of S.

OpenStudy (anonymous):

oh makes sense

OpenStudy (joannablackwelder):

:) Can you try N2O5?

OpenStudy (anonymous):

would N be -5

OpenStudy (anonymous):

5

OpenStudy (joannablackwelder):

Remember that O is virtually always -2.

OpenStudy (anonymous):

10

OpenStudy (anonymous):

you said because of that oxygen would be -10 and the sum would need to be 0 so Nitrogen needs to be 10

OpenStudy (joannablackwelder):

But there are 2 N.

OpenStudy (joannablackwelder):

So each one needs to be 5.

OpenStudy (anonymous):

I understand why N needs 5 but why does O need 5?

OpenStudy (joannablackwelder):

I'm not sure what you mean.

OpenStudy (anonymous):

you said each one needs 5 I do understand why nitrogen needs 5 to off set oxygens -10 right?

OpenStudy (joannablackwelder):

The oxidation number of N needs to be 5 (total of 10) to balance the oxidation number of O (total of -10).

OpenStudy (anonymous):

ok got it. NO3 nitrogen needs 6 right?

OpenStudy (joannablackwelder):

Perfect. :)

OpenStudy (joannablackwelder):

NO2?

OpenStudy (anonymous):

4

OpenStudy (joannablackwelder):

Great!

OpenStudy (anonymous):

the last one I am stumped

OpenStudy (anonymous):

to take a guess 3

OpenStudy (joannablackwelder):

Good guess. Remember how I said that oxygen is almost always is -2. Well, group 2 metals are always +2.

OpenStudy (joannablackwelder):

The rules are summed up on this website. http://www.chemguide.co.uk/inorganic/redox/oxidnstates.html

OpenStudy (anonymous):

-3 then if that is the case

OpenStudy (joannablackwelder):

Exactly.

OpenStudy (joannablackwelder):

You probably have the rules somewhere in your textbook too.

OpenStudy (anonymous):

light bulb. I am starting to understand this chemistry stuff with only 4 weeks left in the semester. awesome.

OpenStudy (joannablackwelder):

Nice. Well, better late than never. :)

OpenStudy (anonymous):

I have the textbook right next to me and honestly it is like reading a foreign language at times.

OpenStudy (joannablackwelder):

Yeah, I know what you mean. Some are better than others.

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