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OpenStudy (abb0t):
is this a medical emergency?
OpenStudy (anonymous):
\[\huge \bf CH_3CH_2CH_2D\]
where D=Deuterium
OpenStudy (abb0t):
And, what is your question?
OpenStudy (anonymous):
is this a hydrocarbon?
OpenStudy (abb0t):
I would say so, yes. Deuterium is an isotope of Hydrogen
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OpenStudy (anonymous):
are you 100% sure?
OpenStudy (abb0t):
yes. I'm a doctor.
OpenStudy (anonymous):
but my few senior friends said that this compound is not a hydrocarbon.
As you know from the name,hydro only refers to hydrogen and carbon refers to carbon.
In hydrocarbon,not hydrogen's isotopes include in it.
OpenStudy (anonymous):
so can you tell me or prove it that i can prove them wrong by telling theory about this *as you like it)
OpenStudy (abb0t):
D is simply the symbol used to represent the isotope. It is not actually an element. It's still hydrogen, except that it has a proton and a neutron, whereas regular hydrogen does not have it.
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