Ask your own question, for FREE!
Chemistry 8 Online
OpenStudy (anonymous):

Helppp

OpenStudy (abb0t):

is this a medical emergency?

OpenStudy (anonymous):

\[\huge \bf CH_3CH_2CH_2D\] where D=Deuterium

OpenStudy (abb0t):

And, what is your question?

OpenStudy (anonymous):

is this a hydrocarbon?

OpenStudy (abb0t):

I would say so, yes. Deuterium is an isotope of Hydrogen

OpenStudy (anonymous):

are you 100% sure?

OpenStudy (abb0t):

yes. I'm a doctor.

OpenStudy (anonymous):

but my few senior friends said that this compound is not a hydrocarbon. As you know from the name,hydro only refers to hydrogen and carbon refers to carbon. In hydrocarbon,not hydrogen's isotopes include in it.

OpenStudy (anonymous):

so can you tell me or prove it that i can prove them wrong by telling theory about this *as you like it)

OpenStudy (abb0t):

D is simply the symbol used to represent the isotope. It is not actually an element. It's still hydrogen, except that it has a proton and a neutron, whereas regular hydrogen does not have it.

OpenStudy (anonymous):

okk...thank you so much..

OpenStudy (anonymous):

@chmvijay

OpenStudy (anonymous):

thank you :)

OpenStudy (chmvijay):

what @abbot said is right :P

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!