Question

Find the derivative.
h(z)=e^-z^2/z

Answer 1

You mean this?\[h(z)=\frac{e ^{-z^2} }{ z}\]

Answer 2

h(z)=e^(-z^2/z)

Answer 3

apply the chain rule:
\[e ^{\frac{ -z^2 }{ z }}=(\frac{ -z^2 }{ z})'*e ^{\frac{ -z^2 }{ z }}\]

Answer 4

would you mind showing me how to do this?

Answer 5

i just did
ask me what's unclear

Answer 6

what would the answer be for this problem? I have two answers but I do not think either one is right

Answer 7

I will continue even if the answer is almost obvious\[(\frac{ -z^2 }{ z })'*e ^{\frac{ -z^2 }{ z }}=(-z)'*e ^{-z}\]

Answer 8

okay, thanks that actually was one of my answers