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Mathematics 17 Online
OpenStudy (anonymous):

Which statement describes the function y = axn when a = 1 and n is even? (I know it's not the first or the second, but I don't know how to determine which of the other two options is the answer.) The graph opens down. The graph is symmetric about the x axis. The graph passes through (–1, 1), (0, 0), and (1, 1). The graph has more than one x intercept.

OpenStudy (anonymous):

Just make n an easy even number like 2. Now plug in -1, 0 and 1 for x and see what you get for y.

OpenStudy (anonymous):

Could you tell me if I did this right?

OpenStudy (anonymous):

If you're asking if that's the graph of y = 1 x^2....The top parabola is the graph of that function...not the stuff below the x-axis.

OpenStudy (anonymous):

I'm sorry. I forgot to explain the graph. I plugged in all 3 equations: y=1x^2 is the parabola above the x axis. y=-1x^2 is the parabola below the x axis. y=0^2 didn't show up because when solved it cancels itself out.

OpenStudy (anonymous):

y = 0^2 should be just a straight flat line drawn right on top of the x-axis. That's probably why you can't see it. It is essentially the x-axis

OpenStudy (anonymous):

Oh yeah that would make sense. What do I do next?

OpenStudy (anonymous):

@BangkokGarrett

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