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Mathematics 16 Online
OpenStudy (anonymous):

Help with riemann sum notation medals!!

OpenStudy (anonymous):

OpenStudy (anonymous):

this is a more interesting version of what you had before, but the concept is still the same.

OpenStudy (anonymous):

this pellet looks complicated

OpenStudy (anonymous):

yeah i tried to go ahead and factor it out and got (5/n)((3k-9)/n)

OpenStudy (anonymous):

you want to make this as easy as possible, so take out a 5/n from the sum, and you are left with a sum with f(a+deltax),

OpenStudy (anonymous):

you didn't factor that correctly, there is no 1/n left over inthe sum

OpenStudy (anonymous):

sheeit

OpenStudy (anonymous):

it is only 3 deltax - 9

OpenStudy (anonymous):

set a as -9, b as 14

OpenStudy (anonymous):

I was thinking of setting a as -9 but wouldn't b-a equal 23

OpenStudy (anonymous):

oops, I done goofed

OpenStudy (anonymous):

yah dun dun it

OpenStudy (anonymous):

set b = -4, a =-9

OpenStudy (anonymous):

-4-(-9)=13

OpenStudy (anonymous):

no, -4-(-9)=-4+9=5

OpenStudy (anonymous):

god damn i typed it into my calculator incorrectly, wasn't paying attention. i dun goofed

OpenStudy (anonymous):

so f(x) is?

OpenStudy (anonymous):

Ah, I'm sorry, let me revise again haha. to make this even easier, factor 3 out again from the sum and youre left with 3(5k/n-3) so set "a" to -3, "b" to 2

OpenStudy (anonymous):

then the f(a+x) is just 3x :D

OpenStudy (anonymous):

don't factor it OUT of the sum, but factor it from the expression you are summing (had to clarify)

OpenStudy (anonymous):

bueno

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