Mathematics
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OpenStudy (ammarah):
What term is needed to add to each side to complete the square?
x2x^+5x=7
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OpenStudy (ammarah):
@ganeshie8
OpenStudy (ammarah):
i divided it by 2 all the coefficents
OpenStudy (ammarah):
sorry theres no x in the front
OpenStudy (ammarah):
just 2x^2
ganeshie8 (ganeshie8):
\(\large 2x^2+5x = 7\)
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ganeshie8 (ganeshie8):
like this ?
OpenStudy (ammarah):
yes
ganeshie8 (ganeshie8):
yes, after dividing, just take half of the x coefficient,
and square it
ganeshie8 (ganeshie8):
\(\large x^2+\frac{5}{2}x = \frac{7}{2}\)
ganeshie8 (ganeshie8):
whats half of \(\large \frac{5}{2}\) ?
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OpenStudy (ammarah):
2.5
ganeshie8 (ganeshie8):
half of \(\large \frac{5}{2}\) is \(\large \frac{5}{2}/2 = \frac{5}{4}\)
ganeshie8 (ganeshie8):
square it and add both sides
OpenStudy (ammarah):
oh lol
OpenStudy (ammarah):
but squaring it gives a decimal
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ganeshie8 (ganeshie8):
:)
\(\large x^2+\frac{5}{2}x + \left(\frac{5}{4}\right)^2 = \frac{7}{2} + \left(\frac{5}{4}\right)^2\)
ganeshie8 (ganeshie8):
left hand side can be written as a perfect square : a^2 + 2ab + b^2 = (a+b)^2
ganeshie8 (ganeshie8):
and, \(\large \left(\frac{5}{4}\right)^2 \) is the term we needed to add both sides in order to do that
ganeshie8 (ganeshie8):
see if that looks okay...
OpenStudy (ammarah):
ok
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OpenStudy (ammarah):
what then?
ganeshie8 (ganeshie8):
we're done
ganeshie8 (ganeshie8):
simplify
ganeshie8 (ganeshie8):
\(\large \left(\frac{5}{4}\right)^2\)
\(\large \frac{25}{16} \) is the term to be added both sides,
ganeshie8 (ganeshie8):
oh wait a sec, u need to multiply 2 both sides cuz u have only 7 on rihgt hand side initially
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ganeshie8 (ganeshie8):
so the term to be added is :
\(\large \frac{25}{8} \) is the term to be added both sides
ganeshie8 (ganeshie8):
u have options for this ?
OpenStudy (ammarah):
ok how about 2x^2-32x=56 i solved it and got x^-16=28
ganeshie8 (ganeshie8):
\(\large 2x^2 -32x = 56\)
divide by 2 both sides :
\(\large x^2 -16x = 28\)
ganeshie8 (ganeshie8):
take half of "x" coefficient, and add its square both sides
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ganeshie8 (ganeshie8):
half of 16 is 8,
so add 8^2 both sides
ganeshie8 (ganeshie8):
\(\large 2x^2 -32x = 56\)
divide by 2 both sides :
\(\large x^2 -16x = 28\)
add 8^2 both sides :
\(\large x^2 -16x +8^2= 28 + 8^2\)
OpenStudy (ammarah):
ok is that my final equation?
OpenStudy (ammarah):
so 64
ganeshie8 (ganeshie8):
yes, left side can be written as perfect square. so we're done
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ganeshie8 (ganeshie8):
yes, its either 64 or 128
ganeshie8 (ganeshie8):
depends on whatever options you're given
ganeshie8 (ganeshie8):
cuz, earliear u have divided 2 both sides right ?
ganeshie8 (ganeshie8):
so to account for that u need to multiply 2 both sides again
ganeshie8 (ganeshie8):
so, answer can be either 64 or 128
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ganeshie8 (ganeshie8):
whatever exists in ur options, tick that
OpenStudy (ammarah):
ok....