Having trouble with basic integration please help. MEdals!
This is a property of integrals I believe.
So, you see that the limits of the very first integral go from -3 to 6. That's the domain we are integrating over.
I'll write it in a general form, and I hope you understand it. :3 \[\int\limits_{a}^{c} f(x) dx = \int\limits_{a}^{b} f(x) dx + \int\limits_{b}^{c} f(x) dx\]
I was trying to use this property but I thought I could just add a negative to the integral to flip the limits. Then i got confused :(
Nooo, that's added work and we don't need that.
So, we're given the value of two integrals within that domain, and we're solving the remaining one. For the first question.
I confused though, how am I supposed to take -3 to the bottom limit?
:o What are you talking about? Are we doing the first part? lol
-3 is less than 0. We're not doing anything fancy except using that property I showed ya.
The full integral goes from -6 to 3. We have integrals for -6 to -3 and 0 to 3. If we add up all those integrals within the full integrals, we can get the full integral. 10 = 12 + ? + 3
What we're trying to find is the integral that goes from -3 to 0.
ok so negative 5, I see..so i was looking at it the wrong way. I was viewing the integrals as separate problem..
Oh, I see. :o
I guess don't do that then lol.
For this second part, we'll have to use that property where you flip the limits and add the negative sign. \[\int\limits_{3}^{-3} f(x) dx = -\int\limits_{-3}^{3} f(x) dx\]
2 for the second one
You got it. ;)
yeah its a conceptual error, i didn't fully realize how the integral notation fit together
thanks
No prob.
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