I found a solution to a differential equation.
3y^2 - 2ln((x^3) + 1) = C. The eq. is correct according to my book, but they have y cannot = o and x cannot = -1. I understand why they are restricting the x value but with y cannot = 0??

Question

I found a solution to a differential equation.
3y^2 - 2ln((x^3) + 1) = C. The eq. is correct according to my book, but they have y cannot = o and x cannot = -1. I understand why they are restricting the x value but with y cannot = 0??

ganeshie8 · Answer

@eliassaab

ganeshie8 · Answer

i think in ur original different equation, y must be present in the denominator somewhere

ganeshie8 · Answer

whats ur original differential equation ?

anonymous · Answer

Exactly!!! Thanks Ganeshie. So my restriction comes from original??

kainui · Answer

Yes, exactly. @jasonjohnson86 

Although neither of us can be sure since you haven't posted the original differential equation.

ganeshie8 · Answer

post the actual DE... you might be getting some restriction on slope when y = 0 happens in solution curve

ganeshie8 · Answer

More here : http://ecademy.agnesscott.edu/~lriddle/apcalculus/apcentral-domain.pdf