Given the function f(x) = 6(x+2) − 3, solve for the inverse function when x = 21.
for the inverse you're going to switch x and y so your new equation will be x=6(y+2)-3 and then we will solve for x by first adding 3 over so x+3=6(y+2) and then divide by 6 so ((x+3)/6)=y+2 and finally subtract that 2 over leaving you with \[\frac{ (x+3) }{ 6 } -2 = y\] then plug in 21 for x so 21+3 = 24, divide that by 6 and you get 4 and then subtract 2 and you get 2! lemme know if you need more help
Thank you! Could you help me with another question?
yes ma'am throw it up here
Which function below is the inverse of f(x) = x2 − 25?
so I'm gonna make you work a little more on this one but I'll support you through it. okay so the inverse means we will switch x and y so we will have x=y^2 - 25 and were trying to solve for y right?
Yes
so we would go about doing that by first moving the 25 over to the other side by adding it and then to solve for y we must take the square root of the entire other side
so it would be the square root of x+25=y
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