Question

If you have a question ask me. I cannot Guaranteed that i will know the answer but I will try my best.

Answer 1

how would this look graphed? 2(x - y) 4 - 2y

Answer 2

do you want a visual?

Answer 3

plz

Answer 4

ok. ill try

Answer 5

What are the discontinuities of the function f(x) = the quantity x squared minus 16 over the quantity 6x minus 24 ?

Answer 6

wait by the way, is this two equations?

Answer 7

this is what it tells me
Select the graph that best describes the following inequalities and system of inequalities.

2(x - y) 4 - 2y

Answer 8

is there pictures with it?

Answer 9

yes

Answer 10

can you post them it would be easier than drawing it all out. plz. and sorry

Answer 11

nico are you wanting your question answered?

Answer 12

okay

Answer 13

does this help

Answer 14

yes. now one more question hon, is the equation you gave me supposed to be 2 equations or one and you have to solve it?

Answer 15

i have to solve it but don't know how and i think its just one

Answer 16

ok

Answer 17

megan do you know precal?

Answer 18

i just figured something i think you need a < > in it? do you

Answer 19

i don't know

Answer 20

um some. jacky

Answer 21

ur a sophmore what classes are you taking

Answer 22

math classes* im a sophomore too :)

Answer 23

ok. shoot

Answer 24

um im taking geometry right now but we just got into trig

Answer 25

im getting off in 5 minutes btw

Answer 26

oh

Answer 27

but you can try me. and ill try

Answer 28

\[\sin(x+\frac{ \pi }{ 6 })-\cos(x+\frac{ \pi }{ 3 }) =\sqrt{3}sinx\]

Answer 29

maria i think your answer is the 4th one you sent. please dont hold it against me if its wrong

Answer 30

its okay but thank you!!!!

Answer 31

the square root of 3

Answer 32

your welcome hon

Answer 33

jacky did you hear me?

Answer 34

By the sine and cosine subtraction formula:
(a) sin(x - π/6) = sin(x)cos(π/6) - cos(x)sin(π/6)
= sin(x)(√3/2) - cos(x)(1/2)
= (√3/2)sin(x) - (1/2)cos(x).
(b) cos(π/3 - x) = cos(π/3)cos(x) + sin(π/3)sin(x)
= (1/2)cos(x) + (√3/2)sin(x).

So, we have:
[sin(x - π/6) + cos(π/3 - x)]/sin(x)
= [(√3/2)sin(x) - (1/2)cos(x) + (1/2)cos(x) + (√3/2)sin(x)]/sin(x), from above
= [√3*sin(x)]/sin(x), by simplifying
= √3, by canceling sin(x).
i hope this is correct.

Answer 35

i have to go jackie but i hope this helps. if its not the answer your looking for im deeply sorry.

Answer 36

Yess

Answer 37

oh. ok

Answer 38

is one of your options x-4