Question

The loss of mass during the disintegration of an atom of an isotope of mass 215.53 amu is 0.26 amu. Calculate the amount of energy released, in kJ, when 3.42 mg of the isotope disintegrates.

Answer 1

Please help...I have a test tomorrow and this question is part of my homework due at midnight..

Answer 2

1 amu = 931,49 MeV, multiply this by 0.26
1 MeV = 1,602\[*10^{-13} J\]
This is energy in joules.

Calculate amount of substance in 0,00324 g by dividing it with 215,53
Then multiply it by Avogadros constant , you get number of
nucleuses.

Then multiply energy and number