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OpenStudy (anonymous):
a jar contains 7 blue and 6 red. in how many ways can 2 red and 2 blue be chosen?
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OpenStudy (anonymous):
familiar with combination formula?
OpenStudy (anonymous):
yes, c(n,n) ?
OpenStudy (anonymous):
you meant C(n,r) ?
OpenStudy (anonymous):
yes, sorry!
OpenStudy (anonymous):
So there are 7 blue (balls?) and you choose 2. Wouldn't it be C(7,2) ? Same thing for the red ones. C(6,2). By the Counting principle, the total combination is C(7,2) x C(6,2)
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OpenStudy (anonymous):
would that be 21x15?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
Thank you so much!
OpenStudy (anonymous):
np
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