Question

Which of the following are solutions to the equation below?

(4x - 1)2 = 11

Answer 1

\(\Large\color{green}{ \bf (4x - 1)^2 = 11}\)

Do you prefer to complete the square, do a quadratic formula, or factor ?

Answer 2

Quadratic Formula sir

Answer 3

or ma'am

Answer 4

just a teenager, if you want, a sir :) .....

\(\Large\color{green}{ \bf (4x - 1)^2 = 11}\)
I am expanding the left side... (using the rule: (a-b)^2=a^2-2ab+b^2 )

\(\Large\color{green}{ \bf 16x^2-8x+1 = 11}\)
now I am going to subtract 11 from both sides.
\(\Large\color{green}{ \bf 16x^2-8x-10 = 0}\)

Answer 5

just a teenager, if you want, a sir :) .....

\(\Large\color{green}{ \bf (4x - 1)^2 = 11}\)
I am expanding the left side... (using the rule: (a-b)^2=a^2-2ab+b^2 )

\(\Large\color{green}{ \bf 16x^2-8x+1 = 11}\)
now I am going to subtract 11 from both sides.
\(\Large\color{green}{ \bf 16x^2-8x-10 = 0}\)

Answer 6

I got disconnected -:(

Answer 7

It's okay

Answer 8

\(\Large\color{brown}{ \bf 16x^2-8x-10 = 0}\) I am going to factor out of 2...

\(\Large\color{brown}{ \bf 2(8x^2-4x-5) = 0}\)
now I am going to divide both sides by 2, which will just allow me to get rid of the 2 on the left side.

\(\Large\color{brown}{ \bf 8x^2-4x-5 = 0}\)

Good so far ?

Answer 9

Think so

Answer 10

\(\Huge\color{blue}{ \bf \frac{-b±\sqrt{b^2-4ac} }{2a} }\)

Answer 11

\(\Huge\color{blue}{ \bf \frac{-(-4)±\sqrt{(-4)^2-4(8)(-5)} }{2(8)} }\)