Simplify radical 10 times radical 8
How can you factor 8 so it has one factor that's a perfect square?
would radical 8 turn into 2 radical 2?
good, do you see how \[\Large \sqrt{8} = 2\sqrt{2}\]
yes, so when i try to simplify the two together how is that done?
you would use the rule \[\Large \sqrt{x}*\sqrt{y} = \sqrt{x*y}\]
\[\Large \sqrt{10}*\sqrt{8}\] \[\Large \sqrt{10}*2*\sqrt{2}\] \[\Large 2*\sqrt{10}*\sqrt{2}\] \[\Large 2*\sqrt{10*2} \ ... \ \text{Use the rule } \sqrt{x}*\sqrt{y} = \sqrt{x*y}\] \[\Large 2*\sqrt{20}\] What's next?
its it become 2 radical 5?
correct, \[\Large \sqrt{20} = 2\sqrt{5}\] making the final answer to be what?
2 radical 5 is not the final answer?
no, it helps you get there though
do you see how \[\Large \sqrt{20} = 2\sqrt{5}\] ??
yes, i see how we get that but how does this get to the final answer? Am i forgetting a number somewhere?
if you look back up at my steps, you'll see the last step is \[\Large 2*\sqrt{20}\] so you're forgetting that 2* out front
oh, sorry so its is 4 radical 5?
perfect
an alternative way is to multiply the radicands to get 10*8 = 80, then simplify \[\large \sqrt{80}\]
Thank you @jim_thompson5910
you're welcome
I prefer \[ \sqrt{10}\sqrt{8}=\sqrt{80}=\sqrt{(16) 5}=4\sqrt 5 \]
Thank you for showing another way @eliassaab
YW @Marie18
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