Question

What is the molarity of a solution that 85.0 grams of Na2SO4 in 325 ml of solution

Answer 1

I literally just answered a question like this. Molarity = \[\frac{ Moles of Solute }{ Liters of Solution}\]
There are 142 grams in a mole of Na2SO4.
\[\frac{ 85.0g }{ 142 g/mol } = 0.59859154929 moles\]
325 milliliters of solution is equal to .325 Liters.
Putting this back into the equation we get
Molarity =\[\frac{ 0.59859154929 }{ .325 } = 1.84182015166\]
But we are limited to 3 significant figures, so the answer would be
1.84M