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OpenStudy (anonymous):
How do I evaluate this?
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OpenStudy (anonymous):
\[\cos^{-1} (\tan(-\frac{ 3\pi }{ 4 }))\]
OpenStudy (anonymous):
find the value of
\[\tan(\frac{ 3\pi }{ 4 })\]
then use your calculator to perform inverse cosine on that value
OpenStudy (anonymous):
well - that in the parenthesis, typo.
OpenStudy (anonymous):
would i find the tan using the unit circle?
zepdrix (zepdrix):
yes
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OpenStudy (anonymous):
that wont be a special angle though.
OpenStudy (anonymous):
wait. ya it will lol.
OpenStudy (whpalmer4):
It's a special one, alright ;-)
OpenStudy (anonymous):
brainfart.
OpenStudy (anonymous):
so it would be\[-(\frac{ ({\frac{ \sqrt{2} }{ 2 }} }{ \frac{ -\sqrt{2} }{ 2 } }) = -1\]
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OpenStudy (anonymous):
sorry, that should have been a positive 1
OpenStudy (anonymous):
uhh. thats a lot of work to see what tan is in q3 especially since it caused you to make a mistake
OpenStudy (anonymous):
yes. it would be positive 1. now just evaluate arccos(1)
OpenStudy (anonymous):
0?
OpenStudy (anonymous):
or you could look at it where is cosx=1 yes 0 is correct.
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OpenStudy (anonymous):
if your dealing with tangent at any 45 you know that the slope of that line is either 1 or -1
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