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Mathematics 8 Online
OpenStudy (anonymous):

How do I evaluate this?

OpenStudy (anonymous):

\[\cos^{-1} (\tan(-\frac{ 3\pi }{ 4 }))\]

OpenStudy (anonymous):

find the value of \[\tan(\frac{ 3\pi }{ 4 })\] then use your calculator to perform inverse cosine on that value

OpenStudy (anonymous):

well - that in the parenthesis, typo.

OpenStudy (anonymous):

would i find the tan using the unit circle?

zepdrix (zepdrix):

yes

OpenStudy (anonymous):

that wont be a special angle though.

OpenStudy (anonymous):

wait. ya it will lol.

OpenStudy (whpalmer4):

It's a special one, alright ;-)

OpenStudy (anonymous):

brainfart.

OpenStudy (anonymous):

so it would be\[-(\frac{ ({\frac{ \sqrt{2} }{ 2 }} }{ \frac{ -\sqrt{2} }{ 2 } }) = -1\]

OpenStudy (anonymous):

sorry, that should have been a positive 1

OpenStudy (anonymous):

uhh. thats a lot of work to see what tan is in q3 especially since it caused you to make a mistake

OpenStudy (anonymous):

yes. it would be positive 1. now just evaluate arccos(1)

OpenStudy (anonymous):

0?

OpenStudy (anonymous):

or you could look at it where is cosx=1 yes 0 is correct.

OpenStudy (anonymous):

if your dealing with tangent at any 45 you know that the slope of that line is either 1 or -1

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