How do I evaluate this?
\[\cos^{-1} (\tan(-\frac{ 3\pi }{ 4 }))\]
find the value of \[\tan(\frac{ 3\pi }{ 4 })\] then use your calculator to perform inverse cosine on that value
well - that in the parenthesis, typo.
would i find the tan using the unit circle?
yes
that wont be a special angle though.
wait. ya it will lol.
It's a special one, alright ;-)
brainfart.
so it would be\[-(\frac{ ({\frac{ \sqrt{2} }{ 2 }} }{ \frac{ -\sqrt{2} }{ 2 } }) = -1\]
sorry, that should have been a positive 1
uhh. thats a lot of work to see what tan is in q3 especially since it caused you to make a mistake
yes. it would be positive 1. now just evaluate arccos(1)
0?
or you could look at it where is cosx=1 yes 0 is correct.
if your dealing with tangent at any 45 you know that the slope of that line is either 1 or -1
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