The accountant for a chain of appliance stores finds that the monthly profit P (in dollars) by selling x televisions per month by the function:
P(x)= -0.2x^2+76x with 0≤x≤250.
a) How many televisions should be sold to maximize their profit?
b)What is the maximum profit?

Question

The accountant for a chain of appliance stores finds that the monthly profit P (in dollars) by selling x televisions per month by the function:
P(x)= -0.2x^2+76x with 0≤x≤250.
a) How many televisions should be sold to maximize their profit?
b)What is the maximum profit?

anonymous · Answer

Hm...Well, If P(x) = -0.2x^2+76x, and I know that 0≤x≤250, then my maximum profit should come when I sell my maximum number of televisions. 

P(250) = -0.2(250)^2+76(250) = $6500. This is my max profit, while the max number of televisions are being sold; in other words, 250 TV's, because x must be smaller than or EQUAL to 250.

anonymous · Answer

Tell me if I got it right! ^_^

anonymous · Answer

Thank you, I'd let you know as soon as get the results. :)

anonymous · Answer

Coo'!