help me please
you can use either \[\sin(x)=\sqrt{1-(\frac{3}{4})^2}\] or draws a triangle
|dw:1397486051902:dw|
there is a picture of an angle whose cosine is \(\frac{3}{4}\) to find the sine, you need \(b\) which you find via pythagoras as \[b^2+3^2=4^2\\ b^2+9=16\\ b^2=7\\ b=\sqrt7\]
that makes \[\sin(x)=\frac {\sqrt7}{4}\] but there is a problem here
what do i do
whoever wrote this question does not understand trig just because you know the cosine, doesn't mean you know the sine it could be \[\frac{\sqrt7}{4}\] but it could also be \[-\frac{\sqrt7}{4}\] also it should be written as \(\cos(x)\) not cosx not a very convincing display of math education
to get the decimal, use a calculator
http://www.wolframalpha.com/input/?i=sqrt%287%29%2F4 i get about \(.66\) really a very poorly written question where does it come from?
my school
sorry about your school
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