Find the limit of the function by using direct substitution.
The choices are: a. 1 b. pi/2 c. 0 d. 5e^pi/2
@iPwnBunnies @ganeshie8
Direct substitution means we can find the limit by plugging in the value of the limit into x. If it's a real number, that will be the limit as x approaches pi/2 of the function.
I'm confused about the e
so am i
@zimmah
well if you use direct substitute you get \[3e^{\frac{\pi}{2}} \times \cos(\frac{\pi}{2})\] so it should be easy to solve from here
i mean i didn't undestand the graph of 3e to the pith 0ver2
Yeah I don't know what to do with 3e^pi/2
you don't need to know about \[3e^{\frac{\pi}{2}}\] because \[\cos(\frac{\pi}{2}) = 0\] so in evaluating the limit you have \[3e^{\frac{\pi}{2}} \times \cos(\frac{\pi}{2}) = 3e^{\frac{\pi}{2}} \times 0 \]
So that means it is 0
correct, i just arrived home so sorry i couldn't reply earlier but campbell is correct.
the e by the way is similar to pi, except pi is approximately 3.1415926... and e is approximately 2.71828...
if only we have the e part how the limit look like ?
well just graph the curve \[y = 3e^xcos(x)\]
i guess there is an exact value
\[\lim_{x \rightarrow \pi/2} = 3e ^{x}\]
here is your graph
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