Find the distance between P and Q. If neccessary round to the nearest hundredth. 1. P(-3, -2) and Q(3, 6) 2. P(-2, 7) and Q(-6, 4) 3. P(-4, -13) and Q(16, 8) 4. P(-2, 5) and Q(8, 7)
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distance between two points (x1,y1) and (x2,y2) is \[D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \] can you apply it and tell me what you get
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number one would be 4 correct?
not really let's do it step by step P(-3, -2) and Q(3, 6) x2-x1 = 3-(-3) = ?
why did you put the -3 behind? why dont you put it first?
you can do that so it will be -3-3 = ?
6 correct?
so once i have added it all up the final answer is 91 right?
if you use 3-(-3) it would be 6 if you use -3-3 it would be -6 but for both cases you will get the same answer for the distance since you will square it now
so it would be 9.5........
umm let's continue it step by step to get the correct answer 6^2 = ?
36
correct, now for the y y2-y1 = 6-(-2) =?
=8 8^2= 64
correct 36+64=?
100 square root of 100=10
correct answer
so i just do the same for them all?
thank you so much!
yeah do the same for the others you can tell me what you get to check the answers for you
so the next one would be 5 correct?
correct
and the one after that would be 29?
correct too
and the last one is 10.19?
do you have choices for the answer or you have to write it ?
write it down
ok so if we apply the formula we get radical(104) = 10.19803... so if you want to round it to the hundredth it would be 10.2 and if you want to round it to the thousandth it would be 10.198
okay thank you!
glad to help! and good work :)
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