Question

Find the area of a sector with a central angle of 32 degrees and a radius of 8.5 millimeters. Round to the nearest tenth.

Answer 1

\[A=\pi r^{2} \frac{\theta}{360}\]

Answer 2

\[A=\frac{ n }{ 360 }\pi r^2\]
where n is the # of degrees in the central angle of the center. So, if you plug the numbers in then you get
A=(32/360)(pi)(8.5)^2

Answer 3

Right so @jasminenicolecx retriceyou need to do with @twvogels equation provided...

is replace \(\large \theta\) with 32

and replace \(\large r\) with 8.5

Then solve and you will have your area