Does anybody know the Heron's Formula?
To find area of a triangle using side-lengths?
Yes, but do you know the formula/ equation?
For a triangle with side lengths a, b, and c; the formula is: \( \displaystyle A = \sqrt{ s (s - a)(s - b) (s - c) } \) Where \( s = \dfrac{a+b+c}{2} \) Called semi-perimeter, as in a+b+c is perimeter, divide that by 2 for semi, or half the perimeter.
Ok. So which one would I use to find area of a right triangle? Would it be the first equation? : A = s(s-a)(s-b)(s-c)
i think that it's S-B
That depends on how much information is given. For a right triangle, you have two perpendicular legs though, so if you know those two side lengths you just need A = 1/2 base * height
what grade are u in
10th
Both equations do work, though, but A = 1/2 b h is more convenient for a right triangle whose side lengths we know.
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Ok. Do you think you can help me solve this problem then?
Sure. :)
Ok :) The question says to 1) Use Heron's Formula to find the area of this triangle. 2)Verify your answer to part (1) by using the formula A=1/2 bh
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So, our first objective is to find Area using Heron's formula. \( A = \sqrt{ s (s - a)(s - b)(s - c)} \), \( s = \dfrac{a+b+c}{2} \) As with any other formula, we just need to fill out the variables and calculate a result. I like to start with just calculating s first. To find s, you just need the perimeter of your triangle, and then divide by 2. You know how to do that? :)
And, it is not important which variable represents each side, as long as each variable has one side with it.
I have to add all the sides of the triangle, right?
Yep.
Perimeter is 36 in.
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