The equation of line LM is y = 5x + 4. Write an equation of a line perpendicular to line LM in slope-intercept form that contains point (−3, 2).
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OpenStudy (anonymous):
You know the slope of the new line has to have a slope that is the negative reciprocal of LM. start with that
OpenStudy (ranga):
1) What is slope of the line y = 5x + 4?
2) What is the slope of the line perpendicular to the line in step 1?
3) The equation of a line with slope m and passing through the point (x1, y1) is:
y - y1 = m(x - x1). Simplify and put it in the form y = mx + b.
OpenStudy (gabylovesyou):
how do i find the slope
OpenStudy (anonymous):
It's the negative reciprocal of the slope of the original.
The reciprocal is the inverse of a number. like so:
8 -> -1/8
OpenStudy (gabylovesyou):
ok.. i have to find the slope of what
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OpenStudy (anonymous):
The original line.
what is the slope of y=5x+4?
OpenStudy (gabylovesyou):
how do i find that
OpenStudy (ranga):
Compare it to y = mx + b where m is the slope.
OpenStudy (gabylovesyou):
slope is 5
OpenStudy (anonymous):
What is the negative reciprocal of 5?
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OpenStudy (gabylovesyou):
-1/5
OpenStudy (gabylovesyou):
@cleats
OpenStudy (anonymous):
correct. now we have the following:\[\huge y - y_1 = m(x - x_1) \]
we have m, we have x1 and y1 too
OpenStudy (gabylovesyou):
yes
OpenStudy (anonymous):
plug that stuff in and solve till you get y = mx + b
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OpenStudy (gabylovesyou):
what is y ?
OpenStudy (gabylovesyou):
y1 is the slope ?
OpenStudy (gabylovesyou):
my internet is really bad... thats why i take forever to respond im so sorry
OpenStudy (anonymous):
m is the standard symbol for slope at least in lines.
\[\huge y - y_1 = m(x - x_1)\](x1,y1) = (−3, 2)
m = -1/5
OpenStudy (gabylovesyou):
y - 2 = -1/5(x - -3)
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OpenStudy (anonymous):
yup. start by simplifying the parentheses. then distributing the -1/5
OpenStudy (gabylovesyou):
we have no x so how do i simplify parenthesis ?
OpenStudy (anonymous):
what does minus a -3 mean?
OpenStudy (gabylovesyou):
ummm
OpenStudy (anonymous):
lol i'll just write it out
(x- -3)= x+3
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OpenStudy (gabylovesyou):
oh lol ok ... so it would be -1/3 * x + 3
OpenStudy (gabylovesyou):
i mean -1/5 * x + 3
OpenStudy (anonymous):
y - 2 = -1/5(x + 3)
yeah. distribute the -1/5
OpenStudy (gabylovesyou):
y - 2 = -1/5x + -1/5 + 3 ?
OpenStudy (anonymous):
y - 2 = -1/5x + -1/5 * 3
fixed
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OpenStudy (gabylovesyou):
ok i do -1/5 * 3 ?
OpenStudy (anonymous):
yeah. -3/5
OpenStudy (gabylovesyou):
ok so we have y - 2 = -1/5x + -3/5
OpenStudy (anonymous):
add 2 to both sides aaaand we get?
OpenStudy (gabylovesyou):
y = -1/5x + 7/5
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