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If A ⊂ B, then A ∩ B = A ∪ B. always sometimes never
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For example A = {2, 4, 6} B = {1, 2, 3, 4, 5, 6} A ∩ B = {2, 4, 6} A ∪ B = {1, 2, 3, 4, 5, 6}
In this case, A ⊂ B, but \( A ∩ B \ne A ∪ B\)
What you have to do is look for more cases that might support the original assumption.
Using Venn Diagrams may help with the process.
Depends whether you allow set A or B to be equal. If A = B, then A is subset of B, then A union B = A intersect B So, sometimes it's true
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okay thank you
As far as I know, there is no difference between ⊆ and ⊂. However, depends on your instructor, ⊆ could mean the usual subset, while ⊂ is the proper set. If ⊂ means proper set, then statement above is always false
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