Find the exact value
Find the exact value of \[\cos (\theta + \phi)\] given that \[\cos \theta = \frac{ 12 }{ 13 } and \cos \phi= \frac{ 4 }{ 5 }\] and that \[\theta and \phi\] are between \[0 and \frac{ \pi }{ 2 }\]
you need the sine of both of those angles
then you can use \[\cos (\theta + \phi)=\cos(\theta)\cos(\phi)-\sin(\theta)\sin(\phi)\] so what is missing is \(\sin(\theta)\) and \(\sin(\phi)\) do you know how to find them?
these are sides of very familiar right triangles |dw:1397513116694:dw|
draw a triangle and use Pythagorean therom?
exactly but as i said, these are familiar right triangles with integer sides, so finding them might come from memory
And then I use the sum and difference formula correct?
yes, you can use the formula i wrote above
\[\cos (\theta + \phi)=\cos(\theta)\cos(\phi)-\sin(\theta)\sin(\phi)\] \[=\frac{12}{13}\times \frac{4}{5}-\frac{5}{13}\times\frac{3}{5}\] then some arithmetic
i jumped the gun and told you what the answers were to the other side of the triangles, but i assume you have seen a 3 - 4 - 5 right triangle and a 5 - 12 - 13 right triangle, so those numbers were easy enough to find
Okay, I got it! Would I use the same method to solve: Given that \[\sin \theta = -\frac{ 4 }{ 5 }\] with theta in quadrant IV,find \[\sin 2\]
yes, sorry i got locked out that is right, what you said, use \[\sin(2\theta)=2\sin(\theta)\cos(\theta)\]
Does the restriction of quadrant 4 have any affect on the answer?
And why did I use the sum and difference formula in the first equation and a double angle formula in this one?
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