Question

Would someone mind checking my work?

Give me a sec to draw :)

Answer 1

b=9 c=9 A=40 degrees

Answer 2

Use the trig identity: a^2 = b^2 + c^2 - 2bc cos A
b = 9; c = 9, cos A = cos 40 deg = 0.77

Answer 3

So what if
a=14 b=18.5 and c=21 @thu1935

Answer 4

We were told to use \[\frac{ 1 }{ 2 } ab \sin of the \angle\] i dont know how to make it a 0 with a line in it

Answer 5

If you know the 3 sides a, b and c, then, use this trig identity to find the angles A, B, and C:
a^2 = b^2 + c^2 - 2bc cos A.
a = 14; b = 18.5; c = 21. Find angle A
2bc*cos A = b^2 +c^2 - a^2 = 342.25 + 441 - 196 = 587.25
cos A = 587.25/2bc = 587.25/777 = 0.76 = cos 40.54
A = 40.54 deg
Use the trig identity a/sin A = b/sin B = c/sin C to find <B and <C