In a lottery there are 9 balls, numbered 1 to 9, in each of three bins. One ball will be selected from each bin. What are the odds of the numbers 2, 3, and 4 being pulled IN THAT ORDER?

Question

anonymous · Answer

are the balls replaced?

anonymous · Answer

There is only 1 way to get 2,3,4 in that order. The total number of ways for the 3 balls is 9*8*7 = 504.
So, success = 1, total = 504, fail = 503.
odds = success / failure, so 1:503.

anonymous · Answer

1/3

anonymous · Answer

But they are in different bins .@PeachRings I am confused .. @akshay1234  that's not a choice.

acxbox22 · Answer

you can pull a 2 out of 9 numbers so the chance is 1/9
you can then pull 3 out of 9 numbers the chance is again 1/9
finally you can pull 4 out of 9 numbers that is also 1/9 chance
1/9 x 1/9 x 1/9= 1/ 729

anonymous · Answer

728 is a choice but not 729 @acxbox22

anonymous · Answer

@david111 they are different bins . Would it still be1; 503 ?

acxbox22 · Answer

are you sure?

anonymous · Answer

I am positive .

anonymous · Answer

acxbox should be right by my math

anonymous · Answer

whats the choices

anonymous · Answer

i believe its 1;503

anonymous · Answer

@david111 
1 to 8 
1 to 80
1 to 503 
1 to 728

anonymous · Answer

Well my answer was on target so it's up to you

anonymous · Answer

a

acxbox22 · Answer

i googled it and 1/503 is your answer but it looks like @david111 copied and pasted her answer http://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.250330.html here is proof no offence meant though

anonymous · Answer

so that means im right haha

anonymous · Answer

@david111 @acxbox22  I am about to post one other one . See if you agree with my answer I put on that one .