a closed manometer with an atomospheric pressure of 3.57 atm the mercury level is lower by 47 mmhg in the arm connected to the gas sample. what is the pressure of gas sample?
can someone guide me through this question so i can solve the others on my own.
Ahh man, I thought it was gonna use the actually gas law. Sorry, Idr how to do these problems. :/
oh ok thanks for trying do you knw anyone that knws how to do this that is on this site
I might. And Ariel probably doesn't know lol.
@Mjones9338 can you help
@anitasonia98 can you help
Ah, alright. So you have to have a conversion between atm and mmHg. :) 1 atm = 760 mmHg. Do you think you could solve the problem now by converting the two (Both of those values should be either in atm or mmHg)?
so i would do 3.57 * 760
Right on :)
Then what would you do? :)
then do i multiply 760 and 47
??
for the first conversion i got 2,713.2 mmhg is that right
Well, you're trying to find the new pressure. The question says that the mercury level is lowered by 47 mmHg. That sounds about right to me. So 2,713.2-47= what?
2,666.2 mmhg or atm ???/
mmHg :)
Now you want to convert that amount back into atm (From the sound of that problem).
how do i do that?
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oh ok i get it thanks can i show you my work for the second problem once i figured it out just to see that i got it
Sure! :)
For the first one? Or second one?
actually the anwser for the first one is 3.5 atm right?
Looks right to me :D What's the second question? :)
the second question is In an open manometer with an atmospheric pressure of 86.5 kPa, the mercury level in the arm connected to the atmosphere is 53 mm Hg lower than in the arm connected to the gas. What is the pressure of the gas sample?
Well, 1 kPa=7.50061683 mmhg... I'm assuming you converted kPa to mmHg? :)
um yea isnt the anwser 648.8 mmhg
Lemme check.
Sorry, kinda fell asleep. Could you show me your work?
@shamil98
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