Question

Please help.. Evaluate..

PS: Credits will be given.. :*

Answer 1

okay

Answer 2

What is the equation?

Answer 3

or problem

Answer 4

\[(\sqrt{x+h}) - \sqrt{x}\]

Answer 5

simplify :)

Answer 6

Um, did you miss something?

Answer 7

there is nothing to simpify, but i bet it might be
\[\frac{\sqrt{x+h}-\sqrt{x}}{h}\]

Answer 8

Uh.. thanks.. @satellite73
How did you know there's an h in the denominator?

Answer 9

just a lucky guess is all
am i right?

Answer 10

gimmick is to multiply top and bottom by the conjugate of the numerator
in no way is this "simplifying" it is just rewriting it

Answer 11

\[\frac{\sqrt{x+h}-\sqrt{x}}{h}\times \frac{\sqrt{x+h}+\sqrt{x}}{\sqrt{x+h}+\sqrt{x}}\]

Answer 12

the numerator then is easy to deal with , it is
\[\frac{x+h-x}{h(\sqrt{x+h}+\sqrt{x})}\] then combine like terms to get
\[\frac{h}{h(\sqrt{x+h}+\sqrt{x})}\] and finally cancel the \(h\)

Answer 13

Ah, I see.

Answer 14

\[\frac{ (\frac{ 1 }{ \sqrt{(x+h)+h} + \sqrt{x+h} }) - (\frac{ 1 }{\sqrt{x+h}+\sqrt{x} }) }{ h }\]

Answer 15

HOW ABOUT THIS?

Answer 16

\(\ \dfrac{h}{h} \times \dfrac{1}{\sqrt{x + h} + \sqrt{x}} \)

Answer 17

\(\ \dfrac{h}{h}\) is just 1, as satellite said the h's would cancel out