Help please! (: Integral Problem attached below.
Definition of improper integrals: split up the limits at points of discontinuity and add the integrals.
\[ \int _{-4}^{4}f(x)\;dx =\int _{-4}^{1}f(x)\;dx + \int _{1}^{4}f(x)\;dx = \int _{-4}^{1}7x\;dx + \int _{1}^{4}7\;dx \]
how do i solve each integral? do I derive 7x first or just plug in the values 1 and -4 find the difference then add it to the next integral?
by now you should know how to integrate.
Actually, one little detail I missed: \[ \int _{-4}^{4}f(x)\;dx =\lim_{t\to 1^-}\int _{-4}^{t}f(x)\;dx + \lim_{t\to 1^+}\int _{t}^{4}f(x)\;dx \]
However, in this case the limits are trivial because direct substitution and evaluation will work.
If you don't know the FTC, you can use basic geometric principles. The area for the \(x\ge1\) part is a rectangle, and the area for \(x<1\) is a trapezoid.
I'm still a little confused. on doing integrals, that's why im having a hard time
Do you know how to find anti-derivatives?
doing a derivative backwards. @wio
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