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Mathematics 8 Online
OpenStudy (texaschic101):

somebody check this for me.....

OpenStudy (texaschic101):

This is not a hard problem....my brain is just not quite awake yet.....I got 5/37.

OpenStudy (texaschic101):

http://oi59.tinypic.com/219nrdv.jpg

OpenStudy (ipwnbunnies):

I am getting something more nice.

OpenStudy (texaschic101):

lol.....

OpenStudy (ipwnbunnies):

As in the fraction is nicer. :3

OpenStudy (unklerhaukus):

\[\frac{\left(3^2-\dfrac23\right)\div2\dfrac1{12}+1}{\dfrac34+\left(\dfrac7{16}\times1\dfrac13\times33\right)}\]

OpenStudy (unklerhaukus):

\[=\frac{\left(9-\dfrac23\right)\div\dfrac{25}{12}+1}{\dfrac34+\left(\dfrac7{16}\times33\dfrac{33}3\right)}\]

OpenStudy (unklerhaukus):

\[=\frac{\left(\dfrac{27}{3}-\dfrac23\right)\div\dfrac{25}{12}+1}{\dfrac{12}{16}+\left(\dfrac7{16}\times(33+11)\right)}\]

OpenStudy (unklerhaukus):

\[=\frac{\left(\dfrac{25}3\right)\times\dfrac{12}{25}+1}{\dfrac{12}{16}+\left(\dfrac7{16}\times44\right)}\]

OpenStudy (unklerhaukus):

\[=\dfrac{\dfrac{25\times12}{75}+1}{\dfrac{12+7\times44}{16}}\]

OpenStudy (texaschic101):

this is how I got my answer... ((3^2 - 2/3) / (2 1/12 + 1)) / (3/4 + (7/16 x 1 1/3 x 33)) ((9 - 2/3) / (25/12 + 12/12)) / (3/4 + (7/16 x 4/3 x 33) ((27/3 - 2/3) / (37/12)) / (3/4 + (28/48 x 33) ((25/3) / (37/12)) / (3/4 + 924/48) (25/3 * 12/37) / (36/48 + 924/48) (300/111) / (960/48) 300/111 * 48/960 14400/106560 5/37

OpenStudy (texaschic101):

It looks like I am way off

OpenStudy (unklerhaukus):

\[=\dfrac{\dfrac{300}{75}+1}{\dfrac{12+308}{16}}\]\[=\dfrac{\dfrac{300}{75}+1}{\dfrac{320}{16}}\]

OpenStudy (unklerhaukus):

\[=\color{white}{\dfrac{4+1}{20}}\]\[=\color{white}{5/20}\]\[=\text{ something nice}\]

OpenStudy (texaschic101):

(375/75) / (320/16) 375/75 * 16/320 6000/24000 1/4 did I do that right ?

OpenStudy (unklerhaukus):

yep thats what i got , and it is nice

OpenStudy (ipwnbunnies):

Yes I also got 1/4

OpenStudy (texaschic101):

lol...its a lot better then mine. Thank you so much UnkleRhaukus.....and iPwnBunnues

OpenStudy (unklerhaukus):

Its \[\color{red}{\Big[}\left(3^2-\dfrac23\right)\div2\dfrac1{12}\color{red}{\Big]}+1 \dots\] not \[{\color{red}{\Big[}\left(3^2-\dfrac23\right)\div2\dfrac1{12}+1}\color{red}{\Big]}\] because order of operations say divide be adding

OpenStudy (unklerhaukus):

before*

OpenStudy (texaschic101):

that made a big difference...I see now where I messed up. Thanks alot for explaining

OpenStudy (unklerhaukus):

fun times

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