Question

Help please?
Questions are in the comments.

Answer 1

okay im here to help.

Answer 2

lets do this yeah

Answer 3

1=?
2=?
5=c
6=?
12=a
13=i think b but not shure
16=?
17=?
18=?
i hope that help a little sorry i didn't know everyone

Answer 4

of the question

Answer 5

\[ \(\huge\color{yellow) }\) \]

Answer 6

That's okay. Thanks though.(:

Answer 7

so where they right

Answer 8

Yes

Answer 9

sweet

Answer 10

srry again

Answer 11

No problem. I appreciate the help.

Answer 12

@joseg.77

Answer 13

1) and 2) both

when sample space is collection of events in an actual "experiment", (and not theoretical possibilities) then the calculated probability becomes experimental probability.

Answer 14

3) odds in favor = p/(1-p)
where 'p' is the probability of that event.

here, there are total 6+5 = 11 marbles, and out of which 6 are green,
so, p = green marbles/ total marbles = 6/11
calculate odds in favor by plugging p = 6/11 in p/(1-p)

Answer 15

4) Experimental probability = customers winning/ total number of customers

now 147 out of 156 have not won,
so how many of them won ??

Answer 16

9

Answer 17

4) continued....
take that number and divide it by 156 to get the probability :)

12)
Probability = number of successful events/ total no. of events,
here,
1/3 = number of foul shots / no. of attempts.

here no. of attempts = 90

and no. of shots expected = 90 - no. of foul shots

Answer 18

yes,
so 4th is
9/156
you can reduce this :)

Answer 19

13)
say if there is only 1 question,
so to get it correct, we have probability = 1/2
because you'd either answer true or false (2 possibilities) and only 1 is correct, so 1/2

now if we have 2 questions, and you need both of them to be correct,
so 1st question needs to be correct AND 2nd question needs to be correct,
so, 1/2 times 1/2 = 1/2^2 = 1/4

that was for 2 questions,
for 8 questions, since all of them needs to be correct,
we'd have
P=1/(2^8) =... ?

ask if you have any doubts in any of these questions...

Answer 20

for 16)
use the formula
\(\Large nCr = \dfrac{n! }{(n-r)! r!}\)

here,
n=15, r =3 :)

Answer 21

17)
5 friends can sit among themselves in 5! ways :)
just calculate 5!

Answer 22

18) you want to choose 2 jeans from 7 pairs = 14 jeans
you can do that in
14 choose 2 ways = \(\large 14C2 =...\)

use the same formula given for 16)th
here, n =14 , r = 2

Answer 23

waiting to hear your doubts....if any.

Answer 24

I don't have any doubts, but I am still confused with 13. Other than that, thank you so much!

Answer 25

ok, 13)th
what doubt u have ?

Answer 26

Oh wait. nvm. I understand now. I just missed the formula you put at the bottom.

Answer 27

Thank you, for the help. I really appreciate it. (:

Answer 28

you're most welcome ^_^