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Chemistry 10 Online
OpenStudy (anonymous):

7. What is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.25 M HBr solution?

OpenStudy (anonymous):

write out the equation which is CsOH+HBr=CsBr+H2O moles HBr = .0264L * .25mol/Liter = =.0066 since its a 1 to 1 ratio the moles of HBr=moles of CsOH .0066mol/.03L = .22M CsOH

OpenStudy (anonymous):

CsOH : HBr 1 : 1 so use the formula C1V1 = C2V2

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