intresting integral question integral of x/[(1+x)(1+x^2)] from zero to infinity
\[\int\limits_{0}^{\infty}x \div[(1+x)(1+x^2)]\]
decomp the fraction?
what do you mean by decompose should i multiply both the terms in the denominator
\[\frac{x}{(1+x)(1+x^2)}=A\frac{1}{1+x}+(Bx+C)\frac{1}{1+x^2} \] \[x=A(1+x^2)+(Bx+C)(1+x)\] when x=-1, solve for A
i didi it i got A= -1/2, B=C=1/2
good, A is fine but ill trust you on BC so the A part is a log, and the BC part i believe is also a log ... might split into a log and arctan
\[A\int \frac{1}{1+x}dx+B\int\frac{x}{1+x^2}dx+C\int \frac{1}{1+x^2}dx\]
ok got it but what about infinite as the limit i am getting log of infinite which is infinite so what about that
your limits (a to b) will most likely both have to be limited to 0 and inf, if they dont converge then the sum is infinity
the wolf says it converges ...
|dw:1397576055157:dw|
Join our real-time social learning platform and learn together with your friends!