Question

One more area problem

Answer 1

a=14 b=18.5 c=21

Answer 2

find the angles?
try using law of cosines first

a^2 = b^2 + c^2 - 2abCos(A)

Answer 3

\[14^2=18.5^2+21^2-2(14)(18.5)\cos(A)\]
like that?

Answer 4

the formula is
\[a^2=b^2+c^2-2bccos(A)\]

Answer 5

thats how i thought i wrote it?

Answer 6

a doesn't equal c


also you don't need to find the angles to find the area if you have all side

Answer 7

Okay would u mind showing me how you would set it up ?

Answer 8

heron's formula

Answer 9

\[s=\frac{a+b+c}{2} \]
find s first
then once you find s proceed with finding the area which is
\[A=\sqrt{s(s-a)(s-b)(s-c)}\]

Answer 10

so what is s?

Answer 11

26.75

Answer 12

ok now replace s with 26.75 and replace a with 14 and replace b with 18.5 and c with 21

Answer 13

16179.15?

Answer 14

that number seems really big
i don't think that is the area

Answer 15

137.81 sorry i forgot to square root

Answer 16

I got 127.197

Answer 17

did you round a number getting the final approximation?

Answer 18

before*

Answer 19

youre right i just re entered. guess i types wrong earlier on calc

Answer 20

ok your answer was very close so i figure you were in the right ball park at least

Answer 21

should i just round 127.20?

Answer 22

what does it say to round to?

Answer 23

it doesnt lol

Answer 24

you could say 127.2

Answer 25

ill leave it to be sure. I have 2 more and they are dealing with co sines . would u mind, if you have time?

Answer 26

Or should i open a new question?

Answer 27

And thank you by the way. that was rude of me @myininaya

Answer 28

you're welcome
and you can post your question
if you want my help it will be slow
I'm trying to multi-task

Answer 29

Okay i would like to work with you. Its okay if its slow