Question

using the quadratic formula, what are the solutions to 6p2 + 11p + 5 = 0

Answer 1

so a = 6
b = 11
c = 5

plug those values into the formula
\[x = \frac{ -b + \sqrt{b^2 - 4ac} }{ 2a }\]

Answer 2

thank you, where did you get the 4 from? I am trying to understand this, I can do some of them but have problems with others :(

Answer 3

\[x = \frac{ -11 \pm \sqrt{11^2 - 4(6)(5)} }{ 2(6)}\]
\[x = \frac{ -11\pm \sqrt{121 - 120} }{ 12 }\]
\[x = \frac{ -11 \pm \sqrt{1} }{ 12 }\]

Answer 4

Okay, so in the quadratic formula, 4 is a number that is already there

Answer 5

thank you, I think I am getting the hang of it.........I hope :).........oh ok, I am having a brain freeze

Answer 6

Ha, it happens. the actual formula is the first comment I put. So; \[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a}\]