Question

problem attached inside:)

thank you! :D

Answer 1

problem!

Answer 2

where are you stuck exactly?

Answer 3

not sure where to begin :(

Answer 4

Draw a graph of the function, and the triangle.

The vertical side has a height y, which is equal to e^(-x/2)

Area is half base times height. Height is above, base is x.

Differentiate the area function and find where it's equal to zero, to find the max and min. (keep in mind the 1<x<3 restriction)

Answer 5

So:
Area = 0.5x*e^(-x/2)

Answer 6

okay:)

so from here, what happens?

Answer 7

It's all in the above post :P

Answer 8

ohh okay

so we get \[y'=e ^{-x/2}(0.5-0.25x)\] ?

Answer 9

I think so, i gotta go eat tho. Set it equal to zero, solve for x and find the max and min. Don't forget the original restriction on x.

Area = 0.5x*e^(-x/2)
then plug the x's you found in there for the max/min areas.

Answer 10

ohh okay:)

thanks! have fun eating! hahaha

Answer 11

ohh okay:)

thanks! have fun eating! hahaha