Simplify (1 − sin x)(1 + sin x).
FOIL it out.
If you do it right, it'll give you a trig identity
Use (a-b)(a+b) = a^2-b^2 and sin^2 + cos^2 = 1 ?
(1- sin x)^2
that is what I got...
(a-b)(a+b) does not equal (a-b)^2
1^2 - sin x ^2 which is 1 - sin x ^2 which is what I got when I FOILED it...
Well correct but remember it will be \[\large 1^2 - sin^2(x)\] so what is \[\large 1 - \sin^2(x) = \space ?\]
Hint would be to remember the identity \[\large \cos^2(x) + \sin^2(x) = 1\]
Yes, I actually have that identity written down. But I am not sure how they tie in together in this problem.
Well...if \[\large cos^2(x) + sin^2(x) = 1\] what would happen if you subtracted \(\large sin^2(x)\) from both sides? \[\large 1 - sin^2(x) = cos^2(x)\]
cos^2 (x) = 1 - sin^2(x)
And you already wrote that... whoopsies.
But then what?
That would be your answer... What you had was to simplify \[\large 1 - sin^2(x)\] Well we just saw that \[\large 1 - sin^2(x) = cos^2(x)\] so your simplification will be \(\large cos^2(x)\)
Oh... okay. I feel really unintelligent at the moment. THANKS!
Don't worry about it, you're very intelligent :) and anytime!
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