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jigglypuff314 (jigglypuff314):
dy/dx = 4y/(x+3)
I need to find the anti-derivative of that, pwease help :3
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OpenStudy (anonymous):
divide both side by y and multiply both sides by dx
OpenStudy (anonymous):
then integrate both sides. Done
jigglypuff314 (jigglypuff314):
dy/y = 4dx / (x+3) ? so that becomes lny on the left
but idk about the right side...
OpenStudy (anonymous):
it's just integrating 4/(x+3) dx
jigglypuff314 (jigglypuff314):
so lny = 4ln(x+3) ?
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OpenStudy (anonymous):
lny = 4ln(x+3) + C
jigglypuff314 (jigglypuff314):
oh right plus C :P
and how do I solve for y? ...
divide both sides by ln?
OpenStudy (anonymous):
XDDDD!!! sorry i just have to laugh a little. you can't dividing both sides by just ln!! it's like dividing both sides by just a square root sign!!
jigglypuff314 (jigglypuff314):
:P yeah... I kinda might have missed the log lesson xD
OpenStudy (anonymous):
ln(y) = x means y = e^x
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jigglypuff314 (jigglypuff314):
so y = e^(4ln(x+3) + C) ?
OpenStudy (anonymous):
right
jigglypuff314 (jigglypuff314):
y = e^(4ln(x+3)) * e^(c) = C e^(4ln(x+3)) ? what else?
OpenStudy (anonymous):
n ln(x) = ln(x^n)
jigglypuff314 (jigglypuff314):
so I should bring the 4 up like
y = C e^(ln((x+3)^4)) ?
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OpenStudy (anonymous):
and e^ln(x) = x
jigglypuff314 (jigglypuff314):
so y = C (x+3)^4 ?
OpenStudy (anonymous):
bingo
jigglypuff314 (jigglypuff314):
Alright :D Thank you!!! ^_^
OpenStudy (anonymous):
yw
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