Question

A spherical fish bowl is half-filled with water. The center of the bowl is C, and the length of segment AB is 12 inches, as shown below. Use Twenty two over seven for pi.

A sphere with diameter 12 inches is drawn.

What is the volume, in cubic inches, of water inside the fish bowl?

339.35

452.57

678.65

904.90

Answer 1

@cheergurl_99 @Chibi_Robo3

Answer 2

i'm not sure if i'm right
so the diameter will be AB=12 in
the formula for the volume of sphere(fish bowl) is \(V_{fishbowl}=\frac{4}{3}\pi r^3\)
since you are only looking for the volume of water, which is half of the fishbowl, divide the volume by two
so the formula will be \(V_{water}=(\frac{4}{3}\pi r^3)(\frac{1}{2})=\frac{2}{3}\pi r^3\)

also you are given the diameter and the formula uses the radius.. so to find the radius, divide the diameter by 2, so it will be r= 6 in
substitute this into the formula \(V_{water}=\frac{2}{3}\pi r^3\) and done :)

Answer 3

904.90

Answer 4

@Chibi_Robo3

Answer 5

can i see your solution?

Answer 6

V=43πr3
12/2=6
V=43∗3.14∗(6)3=1.333∗3.14∗216=904.90

Answer 7

@Chibi_Robo3

Answer 8

where did you get 43? O.o
and remember, you are looking for the volume of water, which is HALF of the volume of the fishbowl

Answer 9

v=4
-
3 not 43 sorry it pop up wrong

Answer 10

Volume of a sphere is V=\[\frac{ 4 }{ 3 }\]
3 πr

Answer 11

@Chibi_Robo3

Answer 12

oh ok...
so i've i said before, you are looking for the volume of water..
you calculated the volume of the fishbowl

Answer 13

and also the question mentioned that \(\LARGE \pi=\frac{22}{7}\)

Answer 14

so i did i wrong its not 904.90

Answer 15

mhmm..
try to follow the instructions i gave you above

Answer 16

please help me

Answer 17

hmm
do the same method as you did before but this time put \(\frac{22}{7}\) for the value of \(\pi\)
then i'll tell you the next thing you have to do