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Mathematics 15 Online
OpenStudy (anonymous):

Diff eq help please!

OpenStudy (anonymous):

Consider the initial value problem: \[y'' + \gamma * y' + y = k*\delta(t-1), y(0) = 0, y'(0) = 0\] where k is the magnitude of an impulse at t = 1 and gamma is the damping coefficient (or resistance). a) Let gamma = 1/2. Find the value of k for which the response has a peak value of 2; call this value k_1. b) Repeat part (a) for gamma = 1/4 c) Determine how k_1 varies as gamma decreases. What is the value of k_1 when gamma = 0?

OpenStudy (abb0t):

Use laplace transform to solve.

OpenStudy (anonymous):

We're currently doing laplace to solve this stuff, so I thiiiink i figured out how to get the solution, but not the k value

OpenStudy (anonymous):

the solution i get is: \[y(t) = \sqrt{\frac{ 16 }{ 15 }}*k*u _{1}(t)*e ^{-(t-1)/4}*\sin(\sqrt{\frac{ 15 }{ 16}}(t-1))\] so when i plug in t = 1, y(t) = 0

OpenStudy (abb0t):

sure.

OpenStudy (anonymous):

so k can't = 2...

OpenStudy (anonymous):

but there's an answer in the book

OpenStudy (abb0t):

@agent0smith may be of more help with differential equations than I can be.

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

Wait come back @agent0smith ! lol Do I have the right idea?

OpenStudy (agent0smith):

I don't know that's why i left :P

OpenStudy (anonymous):

dang it lol. Thanks for trying!

OpenStudy (abb0t):

It's been a few years since I last took this course. But, solve it, like i said, and plug in ur initial conditions to solve for, \(k\).

OpenStudy (anonymous):

alright lol. It doesn't work, so I'm just gonna write the answer down from the back of the book. But thank you for your help!

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