Question

Factor 2x2 + 7x + 3.

A.
(2x + 1)(x + 3)

B.
(2x + 3)(x + 1)

C.
(2x + 5)(x + 1)

D.
The polynomial is prime.

Answer 1

i think A

Answer 2

2x^2 + 7x + 3

2 * 3 = 6

1 * 6 = 6
1 + 6 = 7

2x^2 + x + 6x + 3

x(2x + 1) + 3(2x + 1)

(2x + 1)(x + 3)

Answer 3

So i was correct?

Answer 4

Yes.

Answer 5

Factor 3x2 – 13x + 4.

A.
(3x – 1)(x – 4)

B.
(3x – 2)(x – 2)

C.
(3x – 4)(x – 1)

D.
The polynomial is prime.

Answer 6

@tHe_FiZiCx99

Answer 7

Show me your work?

Answer 8

\[3x ^{2}-13x+4(3x-1)(x-4)\]
=3x+12+1x+4 FOIL METHOD
=13x+4

Answer 9

is that correct

Answer 10

@tHe_FiZiCx99

Answer 11

Um not really.

Take the first coefficient and multiply it by the constant in the back. \(\ 3 \times 4 \) = ?

Answer 12

12

Answer 13

Yes, now the semi hard part is find one number that when multiplied gives you 12 but adds up to your middle term which in this case is -13

Answer 14

No, what number when multiplied gives you 12 but adds up to -13?

Answer 15

never mind thats not correct

Answer 16

Hint: Use negative numbers

Ex: -1 * -5 = 5

But -1 + (-5) = -1 - 5 = -6

Answer 17

@milbes919180 ?

Answer 18

You sure on that?

Answer 19

I have to get off.

-1 * -12 = 12

-1 - 12 = -13

3x^2 - x - 12x + 4

x(3x - 1) -4(3x -1)

(3x - 1)(x -4)

Answer 20

Thats what i answered the first time

Answer 21

You said -12 and 1...

Answer 22

3x2−13x+4(3x−1)(x−4)

=3x+12+1x+4 FOIL METHOD
=13x+4

Answer 23

That's wrong. It doesn't work like that.

Answer 24

u coulda said right answer wrong work

Answer 25

How did you get that answer, if I may ask?

Answer 26

do you not see the (3x-1)(x-4)

Answer 27

I see it. I mean how did you get that answer if you did the process incorrectly?

You used the options. Even if you did use the options, you didn't verify them correctly.