KClO_{3}--- @KCl + 3O_{2}
How many moles of KClO_{3} are needed to produce 50 moles of O_{2}?

Question

KClO_{3}---> @KCl + 3O_{2}
How many moles of KClO_{3} are needed to produce 50 moles of O_{2}?

anonymous · Answer

2KClO3---> 2KCl + 3O2

anonymous · Answer

|dw:1397611372197:dw| you have to use stoicheometry. convert the 50 moles by using the mole to mole ratio making sure units cancel then multiply accross and divide

anonymous · Answer

If this helps to show what has to be done, try to think about this as setting up a proportion based on the mole ratio in the balanced equation, like this:$$\color{green}{\dfrac{2}{3} =\dfrac{x}{50}}$$ Two moles of potassium chlorate is to 3 moles of oxygen, as how many moles of potassium chlorate are to 50 moles of oxygen. Set up the proportion as above, then solve for x.