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Chemistry 21 Online
OpenStudy (anonymous):

Using Ohm's Law, explain how does current change in relationship to voltage, assuming that resistance remains constant

OpenStudy (abb0t):

I = \(\sf \frac{V}{R}\)

OpenStudy (anonymous):

Can you explain how you got your answer

OpenStudy (abb0t):

That's ohm's law.

OpenStudy (anonymous):

I'm sorry. I still don't understand. Is it because the resistance is constant, the voltage is directly proportional to current???

OpenStudy (anonymous):

Abbot, can I ask you another question?

OpenStudy (anonymous):

You, and 3 friends each apply a foce of 163N to push a piano. The amunt of work done is 1762.2J. What distance did the piano move?

OpenStudy (anonymous):

Back to your Ohm's Law question ...\[\color{green}{V = IR \quad V \propto I}\] If the resistance is constant, current and electric potential difference are directly proportional to one another. Doubling the electric potential difference would double the amount of current, and so on.

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