Question

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 2x – 5, and HE = 5y + 2. Find the values of x and y.

A.) x = 39, y = 14
b.) x = 36, y = 13
c.) x = 14, y = 39
d.) x = 13, y = 36

Answer 1

@jim_thompson5910 there

Answer 2

@jim_thompson5910 ?

Answer 3

this is a parallelogram, so the diagonals cut each other in half

Answer 4

what that means is that DH = HF and EH = HG

Answer 5

DH = HF

x+3 = HF ... plug in DH = x+3

x+3 = 3y ... plug in HF = 3y

x = 3y - 3 ... solve for x (by subtracting 3 from both sides)

Answer 6

EH = HG

EH = 2x-5 ... plug in GH = 2x – 5 (note: GH and HG are the same segment)

5y + 2 = 2x-5 ... plug in HE = 5y + 2 (note: EH and HE are the same segment)

Answer 7

so we have 5y + 2 = 2x-5

if you plug in x = 3y - 3, you get

5y + 2 = 2x-5

5y + 2 = 2(3y - 3)-5

now solve for y and tell me what you get

Answer 8

@jim_thompson5910 um i dont have a calculator with me right now and im not so good in math

Answer 9

you don't need a calculator to solve for y

Answer 10

you just need to isolate it on one side

Answer 11

are you familiar with solving equations?

Answer 12

@jim_thompson5910 not really

Answer 13

here's a page that might be helpful

http://www.purplemath.com/modules/solvelin.htm

Answer 14

@jim_thompson5910 so 5y-2=2(3y+3)5 thats going to be the equation

Answer 15

no the equation is given above